Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
Step-by-step explanation:
- y=3/4x+(-5)
- -4x+4(3/4x+-5)=-20
-4x+3x-20=-20
-x=-20+20
-x=0
x=0
y=3/4×{0}-5
y=-5
Answer:
The volume of the cone is approximately 453.0 cm³
Step-by-step explanation:
The volume of a cone is one third that of a cylinder with the same height and radius. That gives us 1/3 πr²h, where r is radius and h is height.
However, we are not given the height of the cone, but the side length. We can work out the height using the Pythagorean theorem, as we have a right triangle with the height, base radius, and length. You may recall that the Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of it's other two sides:
So we can find the height of the cone with that:
Now that we have the cone's height, we can solve for its volume:
For first pound it is = $2.41
For next six, = 0.41 * 6 = $2.46
Remaining = 7.99 - (2.41 + 2.46) = 7.99 - 4.87 = 3.12
Now, additional pounds = 3.12 / 0.39 = 8
Total weight = 1 + 6 + 8 = 15
In short, Your Answer would be 15 pounds
Hope this helps!
24 = x% * 32
24= x/100 * 32
Multiply 100 on both sides.
2400 = x * 32
32x = 2400
Divide 32 on both sides.
x = 2400/32
x = 75
75 percent<span> of 32 is 24</span>
