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marusya05 [52]
3 years ago
10

Dolly borrows $80,000 to purchase a car. The

Mathematics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Interest is $14,400

Step-by-step explanation:

I = Prt

I = (80,000)(0.09)(2)

I = 14,400

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The slope is 2/3 you’re welcome :)
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Monique borrows $5000 for 3 years at 8% per annum simple interest.
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1200 dollars for interest, she must pay 6200

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8 percent of 5000 is 400 times 3 (years) is 1200

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2 years ago
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Write the slope intercept form of the equation of the line described.
Lady bird [3.3K]

Answer:

y= -5

Step-by-step explanation:

x=0 is a vertical graph hence the perpendicular graph would be a horizontal line, a y= ____ graph.

Since it passes through the point (-2, -5),

the equation of the line is y= -5.

This would be in slope- intercept form since the gradient of horizontal lines is zero.

y= mx +c, where m is the gradient and c is the y-intercept.

Given that gradient =0, m=0

y= 0x +c

when x= -2, y= -5,

-5= 0(-2) +c

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c= -5

Thus the equation is y= -5.

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3 years ago
How much time does it take for a squirrel to run 134 meters at a speed of 12 meters per second?
aleksley [76]
11 2/3 seconds at a speed of 12 m/s
4 0
3 years ago
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The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

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