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attashe74 [19]
3 years ago
15

triangle JKM with side j across from angle J, side k across from angle K, and side m across from angle M If ∠J measures 40°, ∠K

measures 90°, and j is 15 feet, then find k using the Law of Sines. Round your answer to the nearest tenth. 9.6 ft 10.4 ft 23.3 ft 154.5 ft
Mathematics
1 answer:
VLD [36.1K]3 years ago
3 0

Answer:

  23.3 ft

Step-by-step explanation:

The law of sines tells you ...

  k/sin(K) = j/sin(J)

Solving for k and filling in numbers, we have ...

  k = sin(K)×j/sin(J) = 1×(15 ft)/sin(40°)

  k ≈ 23.3 ft

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Step-by-step explanation:

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Cos(B) = 3/5 or 0.6

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Step-by-step explanation:

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Solve the equation 2x^2+8x-1=o by completing the square. Give your answer to 2 decimal places
VMariaS [17]

Answer:

\boxed{\sf \ \ \ x=-4.12 \ or \ x=0.12 \ \ \ }

Step-by-step explanation:

Hello,

step 1 - we divide all terms by 2

2x^2+8x-1=0  x^2+4x-\dfrac{1}{2}=0

step 2 - we complete the square

we can notice that

x^2+4x=(x+2)^2-4

so

2x^2+8x-1=0  x^2+4x-\dfrac{1}{2}=0(x+2)^2-4-\dfrac{1}{2}=0\\

step 3 - we move the constant term to the right of the equation

(x+2)^2-4-\dfrac{1}{2}=0\\\\ (x+2)^2=4+\dfrac{1}{2}=\dfrac{8+1}{2}=\dfrac{9}{2}

step 4 - we take the square root on both sides of the equation

x+2=\sqrt{\dfrac{9}{2}}

or

x+2=-\sqrt{\dfrac{9}{2}}

step 5 - we subtract 2 from both sides

x+2=\sqrt{\dfrac{9}{2}} x=\dfrac{3}{\sqrt{2}}-2=0.12132...

or

x+2=-\sqrt{\dfrac{9}{2}} x=-\dfrac{3}{\sqrt{2}}-2=-4.12132...

so the solutions are 0.12 and -4.12

hope this helps

7 0
3 years ago
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