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3 years ago

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triangle JKM with side j across from angle J, side k across from angle K, and side m across from angle M If ∠J measures 40°, ∠K

measures 90°, and j is 15 feet, then find k using the Law of Sines. Round your answer to the nearest tenth. 9.6 ft 10.4 ft 23.3 ft 154.5 ft

1 answer:

VLD [36.1K]3 years ago

3 0

Answer:

23.3 ft

Step-by-step explanation:

The law of sines tells you ...

k/sin(K) = j/sin(J)

Solving for k and filling in numbers, we have ...

k = sin(K)×j/sin(J) = 1×(15 ft)/sin(40°)

k ≈ 23.3 ft

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josephine has three chemistry books, three history books, and nine statistics books. she wants to choose one book of each type t

larisa86 [58]

She can choose three books in 54 ways

What is permutation?

Permutation is a technique involving in which a set or number of things can be ordered or arranged. We use permutation to solve and compute answers

We are given that, Josephine has three chemistry books, three history books, and nine statistics books

She has to choose one from each subject

Firstly She has 3 chemistry books

This can be selected in 3 ways

Then She has 3 history books

This can be selected in 3 ways

Ans finally she has 9 statistics books

This can be selected in 9 ways

Hence total ways in which she can select 3 books is 3*3*9= 54 ways

Hence in 54 ways she can choose three books

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brainly.com/question/1216161

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What is the greatest number that rounds to 500 when rounded to the nearest ten?

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I believe the answer is 549.

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It's D, all real numbers greater than or equal to -3<br> i got %100 in the test

Artyom0805 [142]

Answer:

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Step-by-step explanation:

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I have to get this so I pass help plz

pshichka [43]

Answer:

$\boxed{\sf x=-2}$

$\boxed{\sf y=-4}$

Step-by-step explanation:

<u>First, Let's solve for x in -2x+2y=-4:</u>

$\sf -2x+2y=-4$

<u>Subtract 2y from both sides:</u>

$\sf -2x+2y-2y=-4-2y$

$\sf -2x=-4-2y$

<u>Divide both sides by -2:</u>

$\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}$

$\bold{ x=y+2}$

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

$\sf 3x+3y=-18$

→ let x=2+y

$\sf 3\bold{(2+y)}+3y=-18$

<u>Simplify:</u>

$\sf 6+6y=-18$

<u>Now, let's solve for y in 6+6y=-18</u>

$\sf 6+6y=-18$

<u>Subtract 6 from both sides:</u>

$\sf 6+6y-6=-18-6$

$\sf 6y=-24$

<u>Divide both sides by 6:</u>

$\sf \cfrac{6y}{6}=\cfrac{-24}{6}$

$\bold{ y=-4}$

<u>Now, substitute y=-4 into x=2+y:</u>

$\sf x=2+y$

→ let y = -4

$\sf x=2+\bold{-4}$

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Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

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2 years ago

Solve 5x^2 − 3x + 17 = 9.

Vedmedyk [2.9K]

Answer:

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = $\frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}$

or

x = $\frac{3\pm\sqrt{9-160}}{10}$

or

x = $\frac{3+\sqrt{-151}}{10}$ and x = $\frac{3-\sqrt{-151}}{10}$

or

x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

here i = √(-1)

Hence,

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

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