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Ipatiy [6.2K]
3 years ago
7

How can you write each distance as a fraction? Explain

Mathematics
1 answer:
77julia77 [94]3 years ago
4 0
What is the distance
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A store had 235 MP3 players in the month of January. Every month, 30% of the MP3 players were sold and 50 new MP3 players were s
Gekata [30.6K]
A. would require him to work too many hours, b and c. make no sense, "less than or greater than" no wonder you were puzzled. Only d {none of these] applies.
3 0
3 years ago
The diameter of a pearl is about 4 x 10-3cm and the diameter of an atom is about10-11m. How much larger than an atom is a pearl?
Ugo [173]

Answer:

  • D. 4 × 10⁶ times

Step-by-step explanation:

<u>The diameter of a pearl is </u>

  • 4 × 10⁻³cm = 4 × 10⁻⁵ m

<u>The diameter of an atom is</u>

  • 10⁻¹¹m

<u>How much larger than an atom is a pearl?</u>

  • 4 × 10⁻⁵ ÷ 10⁻¹¹ = 4 × 10⁻⁵⁺¹¹ = 4 × 10⁶ times

Correct option is D

5 0
3 years ago
∠BAD is bisected by . If m∠BAC= 2x - 5 and m∠CAD = 145, the value of x is 150 145 75 70
horsena [70]
We are asked to find the value of x given that ∠BAD is bisected by AC and measurement of BAC is equal to 2x - 5 and measurement of CAD is equal to 145. Since they are bisected, they are equal and the solution is shown below:
m ∠ BAC = m ∠ CAD
2x - 5 = 145 , transpose -5 to the opposite side such as:
2x = 145 + 5 , perform addition of 145 and 5
2x = 150
2x / 2 = 150 / 2 , divide both sides by 2
x = 75

The answer is 75 for the x value.


7 0
3 years ago
Read 2 more answers
PLEASE I NEED THIS NOWWWWWWWWWWWWW
soldier1979 [14.2K]
Answer:
It is A, 65
Hope this helps!
7 0
3 years ago
Read 2 more answers
I need math help. If youre solving a geometric sequence, the equation needed is An=A1Rn-1. If A1= 5 and R= -2. My question was "
CaHeK987 [17]

Answer:

Step-by-step explanation:

an = a1 * r^(n - 1)

a1 = first term = 5

r = -2

n = nth term of the sequence

so it starts with 5

second term is :

an = a1 * r^(n - 1)......for second term

a2 = 5 * -2^(2 - 1) =

a2 = 5 * -2^1

a2 = 5 * -2

a2 = -10

an = a1 * r^(n - 1)....looking for a3

a3 = 5 * -2^(3 - 1)

a3 = 5 * -2^2

a3 = 5 * 4

a3 = 20

an = a1 * r^(n - 1)....looking for a4

a4 = 5 * -2^(4 - 1)

a4 = 5 * -2^3

a4 = 5 * -8

a4 = - 40

an = a1 * r^(n - 1)...looking for a5

a5 = 5 * -2^(5 - 1)

a5 = 5 * -2^4

a5 = 5 * 16

a5 = 80

an = a1 * r^(n-1)...looking for a6

a6 = 5 * -2^(6 - 1)

a6 = 5 * -2^5

a6 = 5 * -32

a6 = -160

4 0
4 years ago
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