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prisoha [69]
2 years ago
5

3 Prove thatcos130°+cos 110+ cos10=0​

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
5 0

We know, cos A + cos B = 2cos(C+D)/2 × cos(C - D)/2

So,

cos 130 + cos 110 + cos 10

cos 130 + 2cos (110+10)/2 × cos( 110-10)/2

cos 130 + 2cos 60 × cos 50

cos ( 180 - 50 ) + 2cos60 cos 50

We know, cos ( 180 - A ) = -cos A

2cos 60 cos 50 - cos 50

Also, cos 60 = 0.5

2×0.5 cos 50 - cos50

cos 50 - cos 50

0  = RHS.

Hence proved

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Item 9 a flight averages 460 miles per hour. the return flight averages 500 miles per hour due to a tailwind. the total flying t
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8 0
3 years ago
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3 years ago
Solve for p. <br> −160=22+8(3p−4)
Aneli [31]
-160=22+8(3p-4)
Use distributive property
-160=22+24p-32
-160=24p-10
Add 10 for both side
-160+10=24p-10+10
-150=24p
Divided 24 for both side
-150/24=24p/24
p=-6.25
Check:
-160=22+8(3p+4)
-160=22+8[3(-6.25)-4]
-160=22+8(-18.75-4)
-160=22+8(-22.75)
-160=22-182
-160=-160. As a result, x=-6.25. Hope it help!
3 0
2 years ago
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