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Citrus2011 [14]
3 years ago
12

Joan has a part-time job at the mall. She works 4 hours every Monday, Wednes

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

20 hours

Step-by-step explanation:

Given ,

She works

Monday = 4 hours

Wednesday = 4 hours

Friday = 4 hours

Saturday = 8 hours

Total = 4 + 4 + 4 + 8

= 20 hrs per week

Joane works 20 hours per week

mr_godi [17]3 years ago
6 0
4*3=12 (4 hours for on three days)

12+8=20 (plus 8 hours for Saturday)

So 20 hours per week
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6. Which expression is equivalent to -21 + 28x?
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Solution,
-28x^2+35x
take the common,
-7x(4x-5)
The answer is -7x(4x-5)
Here,
If we solve,
-7x(4x-5)
Then, the answer would be:
= -7x*4x+7x*5
= -28x^2+35x
Hope it helps
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Answer:

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Step-by-step explanation:

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10^x • 100^2x = 1000^5. Step by Step
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Step one: set the base of each term to be the same (10)
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1. Find <br> A) 35<br> B) 47.5<br> C) 67.5<br> D95
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Step-by-step explanation:

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(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun
love history [14]

Answer:

a) f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11

b) P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286

c) P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857

d) P(X >5 | X \leq 7)

And we can find this probability with this formula from the Bayes theorem:

P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

X \sim Unif (a=4, b =11)

Part a

The probability density function is given by the following expression:

f(x) = \frac{1}{b-a} , a \leq x \leq b

f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11

Part b

We want this probability:

P(X \leq 7)

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}

And replacing we got:

P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286

Part c

We want this probability:

P(5 < X \leq 7)

And we can use the CDF again and we have:

P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857

Part d

We want this conditional probabilty:

P(X >5 | X \leq 7)

And we can find this probability with this formula from the Bayes theorem:

P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5

7 0
3 years ago
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