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3 years ago

15

A rectangular region is removed from another rectangular region to create the shaded region shown below. Find the area of the sh

aded region
4 mm
mm
1 mm
15 mm

1 answer:

Simora [160]3 years ago

3 0

Answer:

wgtvwthrr

Step-by-step explanation:

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Hiiii! help asap, 15 points (:

Pie

The correct answer is C

Good luck on the rest :D

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2 years ago

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Your field experience instructor wants to line up 8 cars for transportation. There are 27 cars available. How many different gro

ValentinkaMS [17]

Answer:

3

Step-by-step explanation:

8*3 is 24 and you cannot add another 8 after that

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3 years ago

What is the value of h in this graph ?<br> F(x)= |x - h|

Misha Larkins [42]

Answer:

$h=4$

Step-by-step explanation:

We know that the vertex(lowest point) of $|x-h|$ is $(h, 0)$ .

By inspection, we can see that the vertex of the graph is $(4, 0)$ .

So, the lowest point of $F(x)=|x-h|$ is $(4, 0)$ , which means $\boxed{h=4}$

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2 years ago

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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3 years ago

Felipe fills an aquarium to a depth of 3/5 meters in 7 1/2 minutes.

dem82 [27]

Answer:

2/25 meters per minute.

Step-by-step explanation:

I believe this is right please correct me if I'm wrong.

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2 years ago

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