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3 years ago

12

A tower casts a 30-foot shadow. At the same time, a person who is 6 feet 6 inches tall casts a 4-foot shadow. How tall is the to

wer?

1 answer:

patriot [66]3 years ago

5 0

5 feet 5 inches? I think

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What is 49 divided by 81 squared

hodyreva [135]

Answer:

0.0074

Step-by-step explanation:

google :/

7 0

3 years ago

Find the value of x. If necessary, write your answer in simplest radical form.<br> 12<br> 9

Kobotan [32]

Answer:

3√7

Step-by-step explanation:

9²+B²=12²

simplify

81+B²=144

minus the 81

B²= 63

3 0

2 years ago

The ________ of an angle is a segment or a ray that passes through the vertex of an angle and splits it into two congruent angle

Yakvenalex [24]

Bisector is the correct answer <span />

4 0

2 years ago

Maria needs to make a total of 80 deliveries this week. So far she has completed 48 of them. What percentage of her total delive

Amiraneli [1.4K]

What I always do to solve this, is find a common factor for each number first.

Usually 4 or 5 works best. I'll use 4.

4 goes into 80 20 times, which means that 4 = 5% of 80.

If 4 = 5%, and 48 = 12 x 4, then 48 must equal 60% of 80.

(Another way to solve this problem is: simplify 48 / 80. This simplifies to 3/5.

3/5 = 60%)!

4 0

2 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

2 years ago