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1 year ago

Okie help help math math math math

Mathematics

2 answers:

V125BC [204]1 year ago

7 0

Answer: 33

Step-by-step explanation: In the problem, you are given the figure with the following:

2x+3 and 3x+12

Method: Lets set this into an equation. Remember that straight lines add up to 180°.

2x+3+3x+12=180° Combine like terms.

5x+15=180°

5x=165°

x=33°

You can always plug in 33° in the expression that was set to make sure it does give you 180°.

Hope this helps.

erik [133]1 year ago

4 0

Answer:

Step-by-step explanation:

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Can someone help me out please?? I would really appreciate it.

maria [59]

Answer:

I can't

Step-by-step explanation:

4 0

2 years ago

(-5/8)×(2/3) what's this answer ?

shutvik [7]

Answer:

Q = -5/8 * 2/3

Multiply both numbers like your multiplying actual numbers.

<h2><em><u></u></em></h2><h2><em><u>A = -10/24 = -5/12</u></em></h2><h2><em><u>Hope this helps</u></em></h2>

6 0

2 years ago

There are 59 people going on a field trip.

Maru [420]

You first multiply 6 and 8 to see how many people are put in the vans without rented a van. This would equal 48. You then subtract 48 from 59 to see how many people still need to be in a van. This would leave you with 11 people. Then you divide 8 from 11 to get 1 3/8. This means you need 2 vans to fit everyone.

3 0

3 years ago

A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

3 years ago

Does 6(3−5w)=5(4−2w)−20w have one solution, no solution, or infinitely many solutions? <br><br> plzz

Vikki [24]

Answer:

No solutions

Step-by-step explanation:

18-30w=20-10w-20w

18-30w=20-30w

18-20=30w-30w

-2 does not equal to 0

No solutions

6 0

2 years ago