Answer:
25
Step-by-step explanation:
We'll compare it with the study of sets, the most noticeable operation of which is:
- <u>n(A ∪ B) = n(A) + n(B) - n(A ∩ B)</u>
where,
n(A ∪ B) is the Union Set, i. e, the set that contains all the elements
n(A) is a subset of the Union Set
n(B) is another subset of the Union Set, and
n(A ∩ B) is the Intersection Set ,i.e, the set contains common elements from both A and B sets.
<h3><u>In the question:</u></h3>
- n(A ∪ B) = ? (<em>the total number of students in the class who are into the above mentioned sports)</em>
Let set A contains the students who play basketball and set B, the students who play Volleyball.
10 students play both of them, i. e.,
- n(A ∩ B) = 10 (<em>as 10 students have common sports - Volleyball and Basketball</em>)
<u>Using the above operation:</u>
=> n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
=> n(A ∪ B) = 25 + 20 - 10
=> n(A ∪ B) = 35
<h3><u>Final Step to the Answer:</u></h3>
<u>The total number of students in the class </u>
= students into the given sports + students who don't play any of them
- Total number of students in the class is 60
- Total number fo students playing basketball and volleyball is 35
The students who play neither = 60 - 35
= 25
Answer:
No, Yes, Yes
Step-by-step explanation:
<em>
</em>
2y = 3 - 5x
y = (3-5x) / 2
<em>F</em><em>A</em><em>L</em><em>S</em><em>E</em>

2P = w + 8
w = 2P - 8
<em>T</em><em>R</em><em>U</em><em>E</em>
<em>
</em>
by = c - ax
y = (c - ax) / b
<em>T</em><em>R</em><em>U</em><em>E</em>
Answer:

and 
Step-by-step explanation:
Given

Required
Express as

In functions:

So, we have:

g(x) can be set to x and f(x) to x + 2
Hence:

When:
and 
<span>
1.) Will yield consecutive odd integers.
k+10, k+12, k+14
or
k+2, k+3, k+4
The answer is k + 10, k +12 , k + 14
Because consecutive integers have difference of 2.
If k is odd, then k+10, k+12, and k+14 are consecutive odd integers.
For example, assume k = 1, then,
k+10=11
k+12=13
k+14=15
And 11, 13 and 15 are consecutive odd integers.
2.) Will yield consecutive integers.
k+1, k+2, k+3
or
k+6, k+8, k+10
The answer is k+1, k+2, k+3
Let k be any integer number, k+1, k+2, k+3 are consecutive integers.
For example, let k = 23
k+1=24
k+2=25
k+3=26
24,25, and 26 are consecutive integers.
</span>