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AnnyKZ [126]
4 years ago
15

Can someone please tell me the answer to these 2 problems. It has to doo with percentages

Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
6 0
1.) 100-82=18 18%=.18= 18/100= 9/50 2.) I need to see the table with the info to help
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IN A CLASS OF 60 STUDENTS, 25 PLAYS BASKETBALL, 2O PLAY VOLLEYBALL, AND 10 STUDENTS PLAY BOTH OF THEM. HOW MANY STUDENTS PLAY NE
I am Lyosha [343]

Answer:

25

Step-by-step explanation:

We'll compare it with the study of sets, the most noticeable operation of which is:

  • <u>n(A ∪ B) = n(A) + n(B) - n(A ∩ B)</u>

where,

n(A ∪ B) is the Union Set, i. e, the set that contains all the elements

n(A) is a subset of the Union Set

n(B) is another subset of the Union Set, and

n(A ∩ B) is the Intersection Set ,i.e, the set contains common elements from both A and B sets.

<h3><u>In the question:</u></h3>
  • n(A ∪ B) = ? (<em>the total number of students in the class who are into the above mentioned sports)</em>

Let set A contains the students who play basketball and set B, the students who play Volleyball.

  • n(A) = 25
  • n(B) = 20

10 students play both of them, i. e.,

  • n(A ∩ B) = 10 (<em>as 10 students have common sports - Volleyball and Basketball</em>)

<u>Using the above operation:</u>

=> n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

=> n(A ∪ B) = 25 + 20 - 10

=> n(A ∪ B) = 35

<h3><u>Final Step to the Answer:</u></h3>

<u>The total number of students in the class </u>

= students into the given sports + students who don't play any of them

  • Total number of students in the class is 60
  • Total number fo students playing basketball and volleyball is 35

The students who play neither = 60 - 35

= 25

5 0
3 years ago
Points P, Q, R and S lie on a line in that order. Q is the midpoint of PR. If the length of RS is 9 and the length of PS is 17,
Marta_Voda [28]
The length of PQ is 10
4 0
4 years ago
Select yes or no for each literal equation.
ch4aika [34]

Answer:

No, Yes, Yes

Step-by-step explanation:

<em>5x + 2y = 3</em>

2y = 3 - 5x

y = (3-5x) / 2

<em>F</em><em>A</em><em>L</em><em>S</em><em>E</em>

\frac{w + 8}{2}  =  p

2P = w + 8

w = 2P - 8

<em>T</em><em>R</em><em>U</em><em>E</em>

<em>ax + by = c</em>

by = c - ax

y = (c - ax) / b

<em>T</em><em>R</em><em>U</em><em>E</em>

6 0
3 years ago
Express the function F in the form f ∘ g. (Enter your answers as a comma-separated list. Use non-identity functions for f(x) and
damaskus [11]

Answer:

F(x) = f \circ g

f(x) = x + 2 and g(x) = x

Step-by-step explanation:

Given

F(x) = x + 2

Required

Express as

F(x) =  f \circ g(x)

In functions:

f \circ\ g(x) = f(g(x))

So, we have:

f(g(x)) = x + 2

g(x) can be set to x and f(x) to x + 2

Hence:

F(x) = f \circ g

When: f(x) = x + 2 and g(x) = x

6 0
3 years ago
Select the correct answer for each statement.
Alex787 [66]
<span>
1.) Will yield consecutive odd integers.

k+10, k+12, k+14
or
k+2, k+3, k+4

The answer is k + 10, k +12 , k + 14

Because consecutive integers have difference of 2.

If k is odd, then k+10, k+12, and k+14 are consecutive odd integers.

For example, assume k = 1, then,

k+10=11
k+12=13
k+14=15

And 11, 13 and 15 are consecutive odd integers.

2.) Will yield consecutive integers.

k+1, k+2, k+3
or
k+6, k+8, k+10

The answer is k+1, k+2, k+3

Let k be any integer number, k+1, k+2, k+3 are consecutive integers.

For example, let k = 23

k+1=24
k+2=25
k+3=26

24,25, and 26 are consecutive integers.
</span>
3 0
4 years ago
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