Answer:
∠J = 60°
Step-by-step explanation:
The Law of Cosines tells you ...
j² = k² +l² -2kl·cos(J)
Solving for J gives ...
J = arccos((k² +l² -j²)/(2kl))
J = arccos((14² +80² -74²)/(2·14·80)) = arccos(1120/2240) = arccos(1/2)
J = 60°
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<em>Additional comment</em>
It is pretty rare to find a set of integer side lengths that result in one of the angles of the triangle being a rational number of degrees.
You subtract 16 from each side of the equation.
Then it will say exactly what number 'n' is.
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The equation is n + 16 = 9
On the left side, you subtract 16 from (n + 16) and you have 'n'.
On the right side, you subtract 16 from 9 and you have -7 .
Now the equation says n = -7
Answer:
she had 16
16
She got c
16 + c
She now has 32
16 + c = 32
I don't know if that's the exact answer, but basically, 16 needs to be added to c, and it needs to equal 32.
Hope this helps! :)
Answer:
we need to see the picture or diagram that corresponds to these problems
Step-by-step explanation:
I cant help you unless I see the picture/diagram that corresponds to these problems
