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Iteru [2.4K]
4 years ago
8

Simplify.

Mathematics
1 answer:
Finger [1]4 years ago
7 0

Answer:

  y^4\sqrt{39y}

Step-by-step explanation:

\displaystyle\sqrt{39y^9}=\sqrt{39y(y^4)^2}=y^4\sqrt{39y}

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where is the question

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3 years ago
Which quadrant in a coordinate plane has two positive points
vodomira [7]

Answer:

The first quadrant

Step-by-step explanation:

Aka upper right quadrant

6 0
3 years ago
which of the following describes how to translate the graph y = |x| to obtain the graph of y = |x-1| -1​
svetoff [14.1K]

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you got to put ylxl

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

5 0
4 years ago
X - y = 4
IrinaK [193]

Answer:

3. 6

Step-by-step explanation:

X - y = 4 ( Equation 1 )

X + y =8 ( Equation 2 )

equation 1 + equation 2

; 2x = 12

x = 12÷2

x =6

hope it helps ☺️

8 0
3 years ago
Read 2 more answers
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