Answer:
32y^2-32
Step-by-step explanation:
4y^2+4(7y^2-8)
4y^2+28y^2-32
32y^2-32
if you need extra steeps explaining then plz let me know and I will help :)
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer: 300
Step-by-step explanation: 300+200=500
then 500-200=300
Answer:
c i believe
Step-by-step explanation:
Answer:
5^15
Step-by-step explanation:
if they have the same base then you add the two top vaules therfore giving you c.
Brainliest plzzzzzzz
