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3 years ago

3x+6y=18 solve for x

2 answers:

8 0

First subtract 6y from both sides of the equation.

$3x+6y-6y=18-6y\Longrightarrow 3x=18-6y$

Then divide both sides of the equation with 3.

$3x=18-6y\Longrightarrow x=\dfrac{18-6y}{3}$

Which further simplifies to.

$x=\dfrac{18}{3}-\dfrac{6y}{3}\Longrightarrow\boxed{6-2y}$

Hope this helps. I tried to made the steps very clear and easy.

r3t40

melamori03 [73]3 years ago

6 0

3x+6y=18

then

3x+6y+−6y=18+−6y

3x=−6y+18

then

3x /3 =( −6y+18) /3

answer

x=−2y+6

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Artyom0805 [142]

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2 years ago

On selling an article for Rs 2300, a shopkeeper made a profit of 15 %. find the cost price of the article.

Ede4ka [16]

Let the cost price of article be x :

x + x × ( 15/100 ) = 2300

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4 0

3 years ago

PLS ANSWER IF GOTTEN RIGHT WILL MARK BRAINLIEST

Mandarinka [93]

B? I’m sorry if I got it wrong

8 0

3 years ago

The height of right circular cylinder P

Radda [10]

Answer:

A. 2

Step-by-step explanation:

The computation is shown below:

As we know that

The Volume of a right circular cylinder is

$V = \pi r^h\\\\$

Here r is the radius

And h is the height

Now it is mentioned that the height of the right circular cylinder P is double to the height of the right circular cylinder Q

Now let us assume h be the height of cylinder p

And, H be the height of cylinder Q

So the equation is

h = 2H ........(1)

Also

The radius of both the cylinders would be the similar length

we assume the r be the radius of both cylinders

Now

The Volume of cylinder Q = $V_Q = \pi r^2H$

And for P it is $V_p = \pi r^2 h$

Now substitute equation 1

$V_p = \pi r^2(2H)\\\\V_p= 2 \pi r^2hH\\\\V_p = 2(\pi r^2H)\\\\V_p = 2(V_Q)$

Hence, the correct option is A.

6 0

3 years ago