<span>Triangles exist:
</span>3 acute angles<span>
2 acute angles, 1 right angle
</span><span>2 acute angles, 1 obtuse angle
</span>
Triangles DON'T exist for:
<span>1 acute angle, 1 right angle, 1 obtuse angle
</span><span>1 acute angle, 2 obtuse angles</span>
Answer:
Algebra
Step-by-step explanation:
Answer:
y = -3/2 x + 4
Step-by-step explanation:
y-4 = -3/2 ( x-0)
y = -3/2 x + 4
H = (-5,5)
I = (1,9)
slope formula : (y2 - y1) / (x2 - x1)
slope = (9 - 5) / (1 - (-5) = 4 / (1 + 5) = 4/6 reduces to 2/3 <==
Answer:
A.2
Step-by-step explanation:
We know that |x|² = 13 and x = 3+bi:
(3+bi)² = 13
3² + b² = 13
9 + b² = 13
Subtract 9 from each side:
9 + b² - 9 = 13 - 9
b² = 4
Take the square root of each side:
√b² = √4
b = 2