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Anna71 [15]
3 years ago
14

What is the product?

Mathematics
2 answers:
lana [24]3 years ago
5 0

Answer:

The correct option is b.

Step-by-step explanation:

We have to find the product of \frac{2a-7}{a}  and  \frac{3a^2}{2a^2-11a+14}.

Multiply both terms.

\frac{2a-7}{a}\times \frac{3a^2}{2a^2-11a+14}

Cancel out the common factor a from numerator and denominator.

\frac{2a-7}{1}\times \frac{3a}{2a^2-7a-4a+14}

\frac{2a-7}{1}\times \frac{3a}{a(2a-7)-2(2a-7)}

\frac{2a-7}{1}\times \frac{3a}{(2a-7)(a-2)}

Cancel out the common factor (2a-7) from numerator and denominator.

\frac{1}{1}\times \frac{3a}{a-2}

\frac{3a}{a-2}

Therefore, the correct option is b.

Ganezh [65]3 years ago
4 0
This question involves factoring and multiplying equations so just follow along my procedures in the image

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B is correct.

Step-by-step explanation:

the median must be 69. only in B the median is 69.

6 0
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Justin is redoing his bathroom floor with tiles measuring 6in by 13 in. the floor has an area of 8,500 in². what is the least nu
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He will need 109 tiles
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5,-5/2,5/4,-5/8 what is the 5th term
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Please help me!<br><br> Thank you
fgiga [73]

The required measures of the angle are given as,
∠JKL = 72°      ∠MLK = 108°      ∠JMK = 36°
∠MJL = 54°       ∠KNL = 90°

Given that.
The measure of the rhombus is given, we have to determine the measure of the angles,

<h3>What is angle?</h3>

orientation of one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as angle.

Here,
∠JKL= 2 × ∠JKM  = 72°
∠MLK = 180 - 2 × ∠JKM =  108°
∠JMK = ∠JKM = 36°
∠MJL = ∠MLK/2 =  54°
The diagonal of the rhombus bisect each other at an angle of 90°
So,
∠KNL = 90°

Thus, all the measure of the angles is shown above.

Learn more about Angles here:
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7 0
1 year ago
Write the quadratic equation whose roots are 5 and 1, and whose leading coefficient is 5
zepelin [54]

Answer: the equation is

5x^2 -30x - 25

Step-by-step explanation:

A quadratic equation is one in which the highest power of the unknown is 2.

The general form of a quadratic equation is expressed as

ax^2 + bx + c

Where c is a constant and a is the leading coefficient

Assuming we want to write the quadratic equation in x, from the information given, the given roots are 5 and 1 and the leading coefficient is 5. We will just multiply the expression by the leading coefficient.

Therefore, the linear factors of the quadratic will be (x-5) and (x-1)

With the leading coefficient as 5, the equation becomes

5(x-5)(x-1)

= 5(x^2 - x - 5x + 5)

= 5(x^2 - 6x + 5)

= 5x^2 -30x - 25

3 0
3 years ago
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