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Sindrei [870]
3 years ago
12

How do you solve 3x-2y=-5 ; 3y-4x=8 for x and y. Explain please.

Mathematics
1 answer:
blagie [28]3 years ago
6 0
3x-2y=-5
3y-4x=8

1) multiply the first equation by 3
   3(3x-2y=-5)   this will give you the new equation: 9x-6y=-15

2) multiply the second equation by 2
   2(3y-4x=8)    this should give you the equation: 6y-8x=16

3) combine both equations/ like terms
    9x-6y=-15
    6y-8x=16

4) -6y and 6y cancel out 
    9x=-15
    -8x=16

5)  9x and -8x combine to make 1x or just x and -15 combined with 16 gives you just 1

6) we are now left with:
    x=1 

7) plug in the x to any of the two original equations ( i chose the first) 
   3x-2y=-5 
   3(1) - 2y = -5
   3 - 2y = -5
   -2y = -8
   y = 4
   When you plug in the x=1 you are given 3(1) - 2y = -5
   Distribute the 3 and you should have 3 - 2y = -5
   Subtract 3 from 3 (this cancels out) then from -5
   This should leave you with -2y = -8 ( -3 and -5 add to -8)
   Divide by -2 ( -2 divided by -2 cancels out) 
   -8 divided by -2 gives you 4 (two negatives make a positive)
   
So, y=4 and x=1
 To check, plug in x=1 and y=4 into one equation. when you're done with that you can plug them into the other. when you plug them into the first equation you get -5=-5 which means they worked. when plugged into the second, the result is 8=8 which means x=1 and y=4 worked for both equations. 

   

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Write the expression in complete factored form. 2a(u+2)+9(u+2)=
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2a(u+2)+9(u+2)

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Step-by-step explanation:

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3 years ago
The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

5 0
3 years ago
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Dafna11 [192]
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