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irina [24]
3 years ago
7

Find the length of segment XM please HELP

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

XM = 7

Step-by-step explanation:

M is the midpoint of XY , thus

XM = MY ( given XY is 7 ) , then

XM = 7

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f(X) = 9x^3 + 2x^2 - 5x^3 - 7x + 4 and g(X) = 5x^3 - 7x + 4. what is f(X) - g(X)? Show all of your steps and write your final an
dolphi86 [110]
First we can simplify f(x) to make it a little easier. We can write it as
4x^3+2x^2-7x+4 by combining like terms

The we just subtract g(x) from f(x) and simplify
4x^3+2x^2-7x+4-(5x^3-7x+4) and remember to distribute the negative to g(x)
4x^3+2x^2-7x+4-5x^3+7x-4 (combine like terms)
-x^3+2x^2
In factored form, this becomes
-x^2(x-2)

Hope this helps
5 0
3 years ago
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Crystal is spinning the spinner at right and claims she has a good chance of having the spinner land on red at least once in thr
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Wouldn’t the answer be 1/3?
6 0
3 years ago
A set of angles has a ratio of 5 to 2. If the larger angle measures 105 degrees then what is the measure of the smaller angle
bekas [8.4K]

ratio 5:2

105, ___

5x = 105 → x = 21

2x = ____ → 2(21) = 42

Answer: 42°

6 0
3 years ago
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A chemist has two alloys, one of which is 15% gold and 20% lead and the other which is 30% gold and 50% lead. How many grams of
vlabodo [156]

Answer: 490 grams of the first alloy should be used.

30 grams of the second alloy should be used.

Step-by-step explanation:

Let x represent the weight of the first alloy in grams that should be used.

Let y represent the weight of the second alloy in grams that should be used.

A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is

0.15x and 0.2x

The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is

0.3y and 0.5y

If the alloy to be made contains 82.5 g of gold, it means that

0.15x + 0.3y = 82.5 - - - - - - - - - - - -1

The second alloy would also contain 113 g of lead. This means that

0.2x + 0.5y = 113 - - - - - - - - - - - - -2

Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes

0.03x + 0.06y = 16.5

0.03x + 0.075y = 16.95

Subtracting, it becomes

- 0.015y = - 0.45

y = - 0.45/- 0.015

y = 30

Substituting y = 30 into equation 1, it becomes

0.15x + 0.3 × 30 = 82.5

0.15x + 9 = 82.5

0.15x = 82.5 - 9 = 73.5

x = 73.5/0.15

x = 490

6 0
3 years ago
Line I is parallel to line m.if the maesure of angle 6 is 75 what is the measure of angle 3
devlian [24]

Answer:

105

Step-by-step explanation:

l is parallel m so angle 3+angle 6=180

8 0
3 years ago
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