Answer:
do u have answer choices or did u come up with anything that can help me out a lil bit
Step-by-step explanation:
mrk me brainliest plz
Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Equation: 4 + 4x + x²
Maxima: No maximum value from said equation
Minima: x = -2 since that is the only critical point in the equation
Answer:
That answer is $37.50
Step-by-step explanation:
You havr to multiply the 125 by .30
Answer:
Children ticket cost $30 and adult ticket costs $40.
Step-by-step explanation:
Given that:
x = price of a child ticket
y = price of an adult ticket
According to given statement;
3x+2y=170 Eqn 1
4x+6y=360 Eqn 2
Multiplying Eqn 1 by 3
3(3x+2y=170)
9x+6y=510 Eqn 3
Subtracting Eqn 2 from Eqn 3
(9x+6y)-(4x+6y)=510-360
9x+6y-4x-6y=150
5x=150
Dividing both sides by 5
Putting x=30 in Eqn 1
3(30)+2y=170
90+2y=170
2y = 170-90
2y = 80
Dividing both sides by 2
Hence,
Children ticket cost $30 and adult ticket costs $40.
