Answer: D. 74.91
One pound is 2.205 kilograms, so we can find how many kilograms are in 165 lbs by dividing 165 by 2.02.
The answer is approximately 74.91
Answer:
therefore the correct options are:
B. the equation is an exponential decay equation.
F. $28000 represents the initial cost of an automobile that depreciates 27% per year over the course of t years.
Step-by-step explanation:
i) the cost of an automobile is given by the equation is
C(t) =
, where C(t) represents the cost and t represents the time in years
ii) the above equation is an exponential decay equation. It is a decay equation because growth rate is 0.73 which is less than 1 and greater than zero.
ii) when t = 0 then the cost is C(0) = 28000 represents the initial cost.
iii) from the equation in i) we can understand that the cost depreciates 27% per year over the course of t years.
therefore the correct options are:
B. the equation is an exponential decay equation.
F. $28000 represents the initial cost of an automobile that depreciates 27% per year over the course of t years.
Answer: i dont know if this will be correct but, the 2 goes on the bottom count 5 up so you will get the first one done, bottom 3 and count up 8, bottom 4 and count up to 13, its the same for all of them.
Step-by-step explanation:
Answer:
<h2>6÷4(7+8) </h2><h2>= 22,5</h2>
<h2>8-6(4+9)</h2><h2>= 26</h2>
<h2>4÷8(9+3)</h2><h2>= 6</h2>
Step-by-step explanation:
<h2>6÷4(7+8)</h2><h3>= 6÷4(15)</h3><h3>= 1,5 × 15</h3><h3>= 22,5</h3>
<h2>8-6(4+9)</h2><h3>= 8-6(13)</h3><h3>= 2 × 13</h3><h3>= 26 </h3>
<h2>4÷8(9+3)</h2><h3>= 4÷8(12)</h3><h3>= 0,5 × 12</h3><h3>= 6</h3>