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Kamila [148]
4 years ago
12

A trapezoid has an area of 400 square millimeters. The bases are 14 millimeters and 36 millimeters. What is the height of the tr

apezoid?
Mathematics
1 answer:
Gennadij [26K]4 years ago
7 0
The height equals to 16
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the bus to Leeds departs every 36 mins and the bus to Manchester leaves every 45 mins they leave the station at 10am one morning
Oliga [24]

Answer:

1 pm

Step-by-step explanation:

We have to find their LCM, or least common multiple

Multiples of 36: 36, 72, 108, 144, 180, 216, ......

Multiples of 45: 45, 90, 135, 180, ....

180 mins is their LCM.

180 mins = 3 hours

10am + 3hours = 1 pm

-Chetan K

6 0
3 years ago
I need help on this question
astraxan [27]

Answer:

uhh

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Help me with this, please!!!!
user100 [1]

Answer: D (1.5,0.5)

Step-by-step explanation:

It's not negative so cross out all those questions that leaves you with C and D. Now we can see that it's past the 1 point so it's in the 1.0 range and0. Range and Cs answer has 3 y on it which is incorrect. So that leaves you with D.

7 0
3 years ago
If f(x) = x2 + 1 and g(x) = x – 4, which value is equivalent to mc024-1.jpg
icang [17]
Given that f(x)=x^2-1 and g(x)=x-4, the value of (f*g)(10) will be:
f*g=(x^2-1)(x-4)
=x^2(x-1)-1(x-4)
=x^3-x^2-x+4
=x^3-x^2-x+4

next we find (f*g)(10), we substitute the value of x in our expression.
(f*g)(10)=10^3-10^2-10+4
=894

5 0
3 years ago
Read 2 more answers
How do I solve problem 7?
miskamm [114]

Answer:

16ᵗʰ Term of the sequence is 1010

Step-by-step explanation:

7.)

Here,

First Term = a₁ = 5

Common Difference = d = 67

Now, For 16ᵗʰ term, n = 16

<em>aₙ = a + (n - 1)d</em>

a₁₆ = 5 + (16 - 1) 67

a₁₆ = 5 + 15 × 67

a₁₆ = 5 + 1005

a₁₆ = 1010

Thus, 16ᵗʰ Term of the sequence is 1010

<u>-TheUnknownScientist</u>

3 0
3 years ago
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