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tekilochka [14]
2 years ago
10

When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probabili

ty, assuming a confidence level of 58%? 0. 21 0. 42 0. 58 0. 79.
Mathematics
1 answer:
svlad2 [7]2 years ago
6 0

Critical probability is the essentially cut-off value. The critical probability when the confidence level of 58% is 0.79.

<h3>What is the critical probability?</h3>

Critical probability is the essentially cut-off value that defines the region where the test statistic is unlikely to lie.

As it is given that the confidence level is 58%. therefore, in order to calculate the critical probability, we need to calculate the margin of error within a set of data, and  it is given by the formula

\rm Critical\ Probability, (P*) = 1-\dfrac{\alpha }{2}

where the value of the α is expressed as,

\alpha= 1 -\dfrac{\rm Confidence\ interval}{100}

Now, as the confidence interval is given to us, therefore, the value of the alpha can be written as,

\alpha= 1 -\dfrac{\rm 58\%}{100} = 0.42

Further, the critical probability, assuming a confidence level of 58% is,

\rm Critical\ Probability, (P*) = 1-\dfrac{\alpha }{2}\\\\\rm Critical\ Probability, (P*) = 1-\dfrac{0.42}{2} = 0.79

Hence, the critical probability is 0.79.

Learn more about Critical Probability:

brainly.com/question/5625386

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Answer: z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

Step-by-step explanation:

let p be the population proportion of students complete their homework on a daily basis.

As per given , we have

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i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(0.28)}{80}}}

That is , z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

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