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kolezko [41]
3 years ago
7

An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.

Mathematics
1 answer:
sdas [7]3 years ago
3 0

Answer:

117

Step-by-step explanation:

every time x goes up by one you add 5 to y

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The distance between the two points pictured is d= Vn
katrin [286]

the distance between points is:

d = 7.8 units

 d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)

 The ordered pairs are:

 (x1, y1) = (- 3, -2)

 (x2, y2) = (2,4)

 By applying the formula we have:

 d = root ((2 - (- 3)) ^ 2 + (4 - (- 2)) ^ 2)

 d = root (61)

 d = 7.8

5 0
3 years ago
Let f(x) = 5x + 4 and g(a) = a2 − 4a + 4 2 . Find the function value. g(−2)
natta225 [31]

Answer:  54

<u>Step-by-step explanation:</u>

replace "a" with "-2" in the g-equation

g(a) = a² - 4a + 42

g(-2) = (-2)² - 4(-2) + 42

        =  4       + 8   + 42

        =  54

7 0
3 years ago
Show solutions please
slega [8]

Answer:

1. Their ages are:

Steve's age = 18

Anne's age = 8

2. Their ages are:

Max's age = 17

Bert's age = 11

3. Their ages are:

Sury's age = 19

Billy's age = 9

4. Their ages are:

The man's age = 30

His son's age = 10

Step-by-step explanation:

1. We make the assumption that:

S = Steve's age

A = Anne's age

In four years, we are going to have:

S + 4 = (A + 4)2 - 2 = 2A + 8 - 2

S + 4 = 2A + 6 .................. (1)

Three years ago, we had:

S - 3 = (A - 3)3

S - 3 = 3A - 9

S = 3A - 9 + 3

S = 3A – 6 …………. (2)

Substitute S from (2) into (1) and solve for A, we have:

3A – 6 + 4 = 2A + 6

3A – 2A = 6 + 6 – 4

A = 8

Substitute A = 8 into (3), we have:

S = (3 * 8) – 6 = 24 – 6

S = 18

Therefore, we have:

Steve's age = 18

Anne's age = 8.

2. We make the assumption that:

M = Max's age

B = Bert's age

Five years ago, we had:

M - 5 = (B - 5)2

M - 5 = 2B - 10 .......................... (3)

A year from now, it will be:

(M + 1) + (B + 1) = 30

M + 1 + B + 1 = 30

M + B + 2 = 30

M = 30 – 2 – B

M = 28 – B …………………… (4)

Substitute M from (4) into (3) and solve for B, we have:

28 – B – 5 = 2B – 10

28 – 5 + 10 = 2B + B

33 = 3B

B = 33 / 3

B = 11

If we substitute B = 11 into equation (4), we will have:

M = 28 – 11

M = 17

Therefore, their ages are:

Max's age = 17

Bert's age = 11.

3. We make the assumption that:

S = Sury's age

B = Billy's age

Now, we have:

S = B + 10 ................................ (5)

Next year, it will be:

S + 1 = (B + 1)2

S + 1 = 2B + 2 .......................... (6)

Substituting S from equation (5) into equation (6) and solve for B, we will have:

B + 10 + 1 = 2B + 2

10 + 1 – 2 = 2B – B

B = 9

Substituting B = 9 into equation (5), we have:

S = 9 + 10

S = 19

Therefore, their ages are:

Sury's age = 19

Billy's age = 9.

4. We make the assumption that:

M = The man's age

S = His son's age

Therefore, now, we have:

M = 3S ................................... (7)

Five years ago, we had:

M - 5 = (S - 5)5

M - 5 = 5S - 25 ................ (8)

Substituting M = 3S from (7) into (8) and solve for S, we have:

3S - 5 = 5S – 25

3S – 5S = - 25 + 5

-2S = - 20

S = -20 / -2

S = 10

Substituting S = 10 into equation (7), we have:

M = 3 * 10 = 30

Therefore, their ages are:

The man's age = 30

His son's age = 10

3 0
3 years ago
How do you do this trig problem.
loris [4]

Consider a right triangle in which one of the angles \theta satisfies

\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35

That is, the side opposite \theta occurs in a ratio of 3 to 5 with the hypotenuse. The side adjacent to \theta then occurs in a ratio of 4 to 5 with the hypotenuse. In other words,

\cos\theta=\dfrac45

because

\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1

Then in this triangle,

\cot\theta=\cot\left(\sin^{-1}\dfrac35\right)=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac45}{\frac35}=\dfrac43

7 0
3 years ago
Z+z+z for x=2, y=-3 , z=-4
REY [17]

Answer:

-12

Step-by-step explanation:

Just sustitute the z for -4

z+z+z

-4+(-4)+(-4)

=-12

I hope this help :)

5 0
3 years ago
Read 2 more answers
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