Given :
Area of rectangle.
To Find :
The dimensions of a rectangle (in m) with area 1,728 m2 whose perimeter is as small as possible.
Solution :
Let, the dimensions of rectangle is x and y.
Area, A = xy.
x = A/y. ....1)
Perimeter, P = 2( x + y )
Putting value of x in above equation, we get :

For minimum P,

SO, it is a square.

Therefore, the dimensions are
.24\sqrt{3}
Hence, this is the required solution.
Answer:
You MADE IT EASY
Step-by-step explanation:

Answer:
Function
Step-by-step explanation:
The following is a <em><u>one-on-one function</u></em> since neither the domain nor the range is being repeated.
Answer:
28
Step-by-step explanation:
let x be the number,
(3/4)x+5=26
(3/4)x=21
x=21*(4/3)
x=28