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pishuonlain [190]
4 years ago
15

Can you help me if it is equivalent or not eqvalent you can help me with the rest if you want the brainless answer

Mathematics
2 answers:
Liono4ka [1.6K]4 years ago
7 0

Answer:

10. Not equivalent.

11. Equivalent

12. Not equivalent

13. Not equivalent

14. Equivalent

15. Can't read, but I think not equivalent.

Basically, if they can be multiplied by the same scale factor they are equivalent, else they aren't.

Step-by-step explanation:

what that guy said :0

skad [1K]4 years ago
5 0
10. Not equivalent.

11. Equivalent

12. Not equivalent

13. Not equivalent

14. Equivalent

15. Can't read, but I think not equivalent.

Basically, if they can be multiplied by the same scale factor they are equivalent, else they aren't.
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vesna_86 [32]
Hope this helps you.

5 0
3 years ago
Learning Task 1: Illustrate the following fractions on your notebook.
Marizza181 [45]

Answer:

The illustration is found in the attachment below.

<em>Note: The correct order of the question is found below:</em>

<em>Learning Task 1: Illustrate the following fractions on your notebook.</em>

<em>a.)2/3 b.)7/9 c.)10/12 d.)8/12 e.)4/5 f.) 8/6 g.)9/4 h.) 28/10</em>

Step-by-step explanation:

a) Draw a rectangle of sides 3 cm by 1 cm. Divide the rectangle into three equal parts. Shade two out of the three parts to give the fraction 2/3

b)  Draw a rectangle of sides 9 cm by 1 cm. Divide the rectangle into nine equal parts. Shade seven out of the nine parts to give the fraction 7/9

c)  Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade ten out of the twelve parts to give the fraction 10/12

d)  Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade eight out of the twelve parts to give the fraction 8/12

e)  Draw a rectangle of sides 5 cm by 1 cm. Divide the rectangle into five equal parts. Shade four out of the five parts to give the fraction 4/5

f)  Draw two rectangle of sides 6 cm by 1 cm. Divide the rectangles into six equal parts each. Shade all the six parts of the first rectangle completely. Then, shade two out of the six parts of the second rectangle to give the fraction 8/6

g) Draw three rectangles of side 4 cm by 1 cm. Divide each of the three rectangles into four parts each. Shade completely the four parts of the first and second rectangle. Then, shade one part out of the four parts of the third rectangle to give the fraction 9/4

h) Draw three rectangles of side 10 cm by 1 cm. Divide each of the three rectangles into ten parts each. Shade completely the ten parts of the first and second rectangle. Then, shade eight parts out of the ten parts of the third rectangle to give the fraction 28/10

6 0
3 years ago
A rectangular field is 0.45 Kilometers long and 0.4 Kilometers wide. What is the area of the field in square meters? Do not roun
nikitadnepr [17]
We have the formula: Area= width x length
And we have Area= 0.45 x 0.4= 0.18 km²= 0.18x1,000,000= 180,000 m²
That is your number
Have fun
7 0
4 years ago
Helpppppppppppppppp!!!
kirza4 [7]

Answer:

I think it would be 71ft

Step-by-step explanation:

Since the cliff was 85ft and she dove 6 ft underwater, the total distance she traveled was 71ft

3 0
2 years ago
Read 2 more answers
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t
Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

<h3>What is sequence ?</h3>

Sequence is collection of  numbers with some pattern .

Given sequence

a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20

We can see that

\frac{a_1}{a_2}=\frac{-10}{5}=-2\\

and

\frac{a_2}{a_3}=\frac{20}{-10}=-2\\

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now n^{th}  term of this Geometric progression can be written as

T_{n}= 5\times(-2)^{n-1}

So summation of 15 terms can be written as

\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0
3 years ago
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