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3241004551 [841]
4 years ago
14

megan read that an early microchip used in a computer could process between 50,000 and 60,000 operations in one second. Which co

uld be the amount processed in five seconds?
Mathematics
1 answer:
KIM [24]4 years ago
3 0

Answer:

250,000 to 300,000 operations could be processed in five seconds.

Step-by-step explanation:

To find the amount that could be processed in five seconds, we just multiply both by 5.

50,000 * 5 = 250,000

60,000 * 5 = 300,000

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PLS HELP ME I WILL GIVE BRAINLIEST
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Answer:

78°

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what will be the total paid on an amortized loan of $15,000 for 5 years at 2 3/4% compounded monthly?
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the loan is being amortized, so that doesn't matter for its future value, the simple case that the borrower is paying it in bits monthly.

so, we're really just looking for the future value of the Principal $15000, let's convert theat mixed fraction to improper fraction, and then to a percent format firstly.


\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}\implies \stackrel{decimal}{2.75} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt}


\bf \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$15000\\ r=rate\to 2.75\%\to \frac{2.75}{100}\dotfill &0.0275\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &5 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0275}{12}\right)^{12\cdot 5}\implies A=15000\left( \frac{4811}{4800} \right)^{60}\implies A\approx 17208.318305


how did we get 4811/4800?   well, is really just the 1+(0.0275/12), which gives us about 1.0022917 but is a repeating decimal, so 4811/4800 is just the fraction version of it.

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He's right if you add 0.003 to itself ten times it equals 0.03

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