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evablogger [386]
3 years ago
14

Among fatal plane crashes that occurred during the past 6565 ​years, 613613 were due to pilot​ error, 7575 were due to other hum

an​ error, 470470 were due to​ weather, 311311 were due to mechanical​ problems, and 342342 were due to sabotage. Construct the relative frequency distribution. What is the most serious threat to aviation​ safety, and can anything be done about​ it?
Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

We have different information and we need to make a table of that, so

cause...................Relative Frequency

Pilot Error............................613

Othe human error.............75

Weather...............................470

Mechanical Problems.....311

Sabotage............................342

Total: 1811

To calculate the relative distribution we need basically divide by the total and multiply for 100.

cause................................Relative Frequency

Pilot Error............................613/1811*100 =33.84%

Othe human error.............75/1811*100 = 4.1%

Weather...............................470/1811*100 = 25.95%

Mechanical Problems.....311/1811*100 = 17.17%

Sabotage...........................342/1811*100 = 18.88%

Total: 100%

So the relative frequency distribution is,

cause...................................Relative Frequency

Pilot Error............................33.84%

Othe human error.............4.1%

Weather..............................25.95%

Mechanical Problems.....17.17%

Sabotage...........................18.88%

Total: 100%

The vast majority of failures are made by pilots. The best thing to do is offer them more training. Many of these problems are due to ignorance of the terrain or carelessness due to the standardized level of security that flights generally have. Lack of practice in extreme situations can cause these problems.

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hram777 [196]

Answer:

1) Maximum number of tables that can be kept in the dinning room is 10 tables

2)The maximum number of customers, given 6 people per table is 60 customers

Step-by-step explanation:

The parameters given are;

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Dimension of table = 2 m by 1.5 m

Number of people at a table = 6 people

Dimension of dinning;

Width = 12 m

Length = 20 m

Dimension of entrance;

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Length = 10 m

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Distance between = 2 × 6 = 12

4.5 + 12 = 16 m (More room required)

With two tables, we have;

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Distance between = 6 m

Dining room width required = 3 + 6 = 9 m

Therefore, the maximum tables in each row = 2

Given that the dining room area extends to the entrance area, total length = 30 m.

With 4 tables we have;

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Length = 3 × 2 + 6 × 2 = 18

Therefore, both arrangements are acceptable;

Just on entering by the right the length = 20/21×30 m

Therefore, with 3 tables will required number due to proximity wit the door and tables arranged along the right wall of the dinning

1) Maximum number of tables that can be kept in the dinning room = 4 + 3 + 3 = 10 tables

2)The maximum number of customers, given 6 people per table = 6×10 = 60 customers.

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