Answer:
more info please
Step-by-step explanation:
Answer: No
Step-by-step explanation:
To get the least possible product, you want both the 2-digit number and the 1-digit number to be as small as possible
The smallest 2-digit number is 10
The smallest nonzero 1-digit number is 1
so the smallest product is 10 * 1 = 10
Step-by-step explanation:
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S = d/t
st = d
t = d/s
The time going is t1.
The time returning is t2.
The total time is 4 hours, so we have t1 + t2 = 4
The speed of the current is c.
The speed going is 9 + c.
The speed returning is 9 - c.
t1 = 16/(9 + c)
t2 = 16/(9 - c)
t1 + t2 = 16/(9 + c) + 16/(9 - c)
4 = 16/(9 - c) + 16/(9 + c)
1 = 4/(9 - c) + 4/(9 + c)
(9 + c)(9 - c) = 4(9 - c) + 4(9 + c)
81 - c^2 = 36 - 4c + 36 + 4c
81 - c^2 = 72
c^2 = 9
c^2 - 9 = 0
(c + 3)(c - 3) = 0
c + 3 = 0 or c - 3 = 0
c = -3 or c = 3
We discard the negative answer, and we get c = 3.
The speed of the current is 3 mph.
Answer:
30"
Step-by-step explanation:
We know:
E = 3*s - 11
E = 79"
Setting them both equal:
79 = 3s - 11
add 11 to both sides
79 + 11 = 3s - 11 + 11
Simplify
90 = 3s
divide both sides by 3
90 / 3 = 3s / 3
Simplify
s = 30"
