I think the third one is the answer
1. The <span>conclusion that can be made about the results of your first cross between a homozygous red bull (RR) and a heterozygous red cow (Rr) is shown below :
You supposed to make a punnet square, so (picture)
</span>Than you will get that the first generation will be 50% homozygous dominant
and 50% heterozygous which lead us to conclusion :
<span>Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).
</span>
2. Conclusion about the results of your second cross between a heterozygous red bull (Rr) and a heterozygous red cow (Rr) is shown in the second picture. And you can see that <span>in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).
3. Conclusion about </span>the results of your third cross between a homozygous white bull (rr) and a homozygous white cow (rr) are shown in the third picture. In this case you can see the result of <span> 100% (homozygous recessive).</span>
Answer:
1/4
Explanation:
Dominance within this multiple-allele series is c+ (agouti) > cch (chinchilla) > ch (himalayan).
A cross between c+/ch x cch/ch was done.
<u>The possible genotypes of the offspring are:</u>
- c+/cch: agouti
- c+/ch: agouti
- ch/cch: chinchilla
- ch/ch: himalayan
So 1/4 of the progeny will be chinchilla.
They will both have controls!