the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130
Concentric as they have same center
Answer:
the answer is c. 44, i hope it works
Step-by-step explanation:
Answer: x = 4
y = - 3
Step-by-step explanation:
The given system of simultaneous equations is expressed as
x-3y = 13 ------------------------1
2x+4y=-4--------------------------2
We would apply the method of substitution in solving the equations. From equation 1, we would make x to stand alone by adding 3y to the left hand side and the right hand side of the equation. It becomes
x - 3y + 3y = 13 + 3y
x = 13 + 3y
Substituting x = 13 + 3y into equation 2, it becomes
2(13 + 3y) + 4y = - 4
26 + 6y + 4y = - 4
26 + 10y = - 4
Subtracting 26 from the left hand side and the right hand side of the equation, it becomes
26 - 26 + 10y = - 4 - 26
10y = - 30
Dividing the left hand side and the right hand side of the equation by 10, it becomes
10y/10 = - 30/10
y = - 3
Substituting y = - 3 into x = 13 + 3y, it becomes
x = 13 + 3 × - 3
x = 13 - 9
x = 4
The correct answer I believe in b
