If 2.5 inches equals 5 miles how far is three inches

The test statistic of zequals2.32 is obtained when testing the claim that pgreater than0.3. a. Identify the hypothesis test as b

Sonja [21]

Answer:

a) We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

b) $p_v =P(z>2.32)=0.0102$

c) So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

Step-by-step explanation:

Part a: Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion p is greatr than 0.3, so then the system of hypothesis are.:

Null hypothesis: $p \leq 0.3$

Alternative hypothesis: $p > 0.3$

Right tailed test

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

For this case the statistic is given by $z_{calc}= 2.32$

Part b: Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.32)=0.0102$

Part c

So the p value obtained was a very low value and using the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is higher than 0.3

6 0

3 years ago

Rewrite the equation in Ax+By=C form

Ksju [112]

Ax + By = C form of the given equation is –6x + y = –28.

Solution:

Given equation is y – 2 = 6(x – 5).

To write the equation in Ax + By = C format:

y – 2 = 6(x – 5)

y – 2 = 6x – 30

Add 2 on both sides of the equation.

y – 2 + 2 = 6x – 30 + 2

y = 6x – 28

Subtract 6x from both sides of the equation.

y – 6x = 6x – 28 – 6x

y – 6x = –28

Arrange the terms in the equation.

–6x + y = –28

This is in the form of Ax + By = C.

Here A = –6, B = 1 and C = –28.

3 0

2 years ago

a box contains 4 red balls and 6 purple balls. Ezra takes out a ball, puts it back and then takes out another ball. what is the

ss7ja [257]

Answer:

16/100 = 4/25

Step-by-step explanation:

4/10 * 4/10 = 16/100

8 0

2 years ago

Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final c

Black_prince [1.1K]

Answer:

The test statistic value Z = 4.64 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

Test the claim that the proportion of all children in the town who suffer not from asthma is 11%

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 167

Given data In a sample of 167 children selected randomly from one town, it is found that 37 of them suffer from asthma.

Sample proportion

$p^{-} = \frac{x}{n} = \frac{37}{167} = 0.2215$

Given Population proportion 'P' = 11% = 0.11

Step(ii) :-

Null Hypothesis : H₀ : p = 11

Alternative Hypothesis H₁: p≠11

Test statistic

$Z = \frac{p^{-} -P }{\sqrt{\frac{P Q}{n} } }$

$Z = \frac{0.2215 -0.11 }{\sqrt{\frac{0.11 X 0.89}{167} } }$

Z = 4.64

step(iii)

Critical value Z = 1.96

The calculated value Z = 4.64 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

Conclusion:-

Test the claim that the proportion of all children in the town who suffer not from asthma is 11%

4 0

3 years ago

Amelia and Joey decided to shoot arrows at a simple target with a large outer ring and a smaller bull's-eye. Amelia went first a

Alona [7]

Answer:

outer ring worth 14 pts

bull's-eye worth 74.333333 pts

Step-by-step explanation:

let the worth point of landing an arrow on the outer ring be "x" and on bull's eye be "y"

For amelia

$3x + 3y = 267$

For joey

$4x + 3y = 281$

subtracting the first equation from the second

$x = 14$

$3x + 3y = 267$

$42 + 3y = 267$

$3y = 223$

$y = 74.333$

3 0

3 years ago