F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Answer: her call lasted for 26 minutes.
Step-by-step explanation:
Let x represent the number of minutes for which her call lasted.
Rachel purchased a prepaid phone card for $30. Long distance calls cost 6 cents a minute using this card. Converting 6 cents to dollars, it becomes 6/100 = $0.06
This means that the cost of x minutes of long distance call is
0.06 × x = $0.06x.
If the remaining credit on her card is $28.44, it means that
0.06x + 28.44 = 30
0.06x = 30 - 28.44
0.06x = 1.56
x = 1.56/0.06
x = 26
Answer:
y = 60x + 20
Step-by-step explanation:
The number of hours that we ski is a variable cost where each hour costs $60. On top of that, we have a fixed cost of $20 which stays the same no matter how long we ski.
So we can use an equation to find the totla cost C given the number of hours t as follows:
C(t) = 60t + 20
We can use this equation to find the cost of a skiing session by plugging in some value for t. For example, if we ski for 3 hours:
C(3) = 60(3) + 20 = $200
The equation can also be written using x and y and mean the same thing.
Answer:
end of third year = 1,200*(1.02)^3 = 1,273.45 plus
end of second year = 1,200*(1.02)^2 = 1,248.48 plus
end of first year = 1,200*(1.02) = 1,224.00
Total = 3,745.9
Step-by-step explanation:
