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DIA [1.3K]
3 years ago
5

How do you add logs with different bases? e.g. log (base 2) y + log (base 4) y = 6 Thanks in advance!

Mathematics
1 answer:
Gemiola [76]3 years ago
3 0

This could be done by shifting bases:

log (base a) b = [log (base 10) b]/[log (base 10) a], *note it could be any other base ( it could be base e)

solving  the given problem: (log y/ log 2) + (log y/log 4) = 6

log y = 1.2041

y = 16 

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