Answer:
roots: 1 and 3
k = 3
Step-by-step explanation:
2 roots: p and p+2
(x-p) (x-p-2) = x² - 4x + k
x² -2px -2x + p² + 2p = x² - 2 (p+1)x + (p² + 2p) = x² -4x + k
-2 (p+1) = -4
p+1 = 2
p = 1 ... root 1
p' = 1+2 = 3 ... root 2
k = p² + 2p = 3
check: (x-1) (x-3) = x² - 4x + 3 = x² - 4x + k
Answer:
C, as q = 62.
Step-by-step explanation:
When you have an equation, your goal is to get the letter you are solving for alone. To do this, you employ a simple rule: what you do to one side of the equals sign, you must do the other.
To isolate q in -55 + q = 7, you must add 55 to the left side. q is now alone. However, because we added 55 to the left side, we must also do it to the right! 7 + 55 = 62, so the new right side is 62. Hence, we get to this:
q = 62
The answer is now in plain sight!
Answer:
20π sq ft ≈ 62.83 sq ft
Step-by-step explanation:
Area of table with diameter 8 ft = π*8^2/4 = 16π
Area of table with diameter 12 ft = π*12^2/4 = 36π
Difference between the area of the tables ;
= 36π - 16π
= 20π sq ft ≈ 62.83 sq ft ( π = 3.14)
Answer:
it would be a 85 percent
Step-by-step explanation:
the solutions to the related equation are 0,2,3 .
<u>Step-by-step explanation:</u>
Here we have , function f(x) = x3 – 5x2 + 6x . Graph of this function is given below . We need to find What are the solutions to the related equation . Let's find out:
Solution of graph means the value of x at which the value of f(x) or function is zero . We can determine this by seeing the graph as at what value of x does the graph intersect or cut x-axis !
At x = 0 .
From the graph , at x=0 we have f(x) = 0 i.e.
⇒ 
⇒ 
⇒ 
At x = 2 .
From the graph , at x=2 we have f(x) = 0 i.e.
⇒ 
⇒ 
⇒ 
At x=3 .
From the graph , at x=3 we have f(x) = 0 i.e.
⇒ 
⇒ 
⇒ 
Therefore , the solutions to the related equation are 0,2,3 .