Answer:
(a) h^-1(x) = (x+6)/6
Step-by-step explanation:
The inverse relation can be found by solving for y: x = h(y).
<h3>Solution</h3>x = h(y) . . . . . the inverse relation
x = 6y -6 . . . . . use the function definition
x +6 = 6y . . . . add 6
(x +6)/6 = y . . . . divide by 6
The inverse function is ...
We have that the workdone in stretching natural length to is mathematically given as
W=9/2lbft
<h3>Workdone in stretching natural length</h3>Question Parameters:
Generally the Hookes equation for the Force is mathematically given as
F=Kx
Where
3.2lb=2ft*k
Thereofore
k=16
Force becomes
f=kx
f=16x
Hence
W=9/2lbft
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