To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
By the way that it is worded, I believe that you are only allowed to put 1 charm on the bracelet, so there are 9 ways to pick a charm.
Hope this helps(and also if you have a more refined wording please put it in the comments)!
Answer:
Step-by-step explanation:
next term is -432
It would be around 9.304. so you'd round to the nearest tenth 9.3
Answer:
There are 3478761 ways to select the first 5 numbers
Step-by-step explanation:
As understood from the statement of this problem we assume that it does not matter the order in which the first 5 white balls are selected.
In this case it is a combination.
So, what we want to know is how many ways you can choose 5 white balls out of 55.
Then we use the formula of combinations:

Where you have n elements and choose x from them.
Then we look for:
