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Cerrena [4.2K]
3 years ago
11

How many ways can five people, A, B, C, D, and E, sit in a row at a movie theater if A and B must sit

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0

Answer:

The total number of ways A, B, C, D, and E can sit together is 5

Step-by-step explanation:

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Hi,


The equation looks like this...

n + 7 \times 2 - 8 \div 2 \\ 3 + 7 \times 2 - 8 \div 2 = 3 + 14 - 4 = 13 \\ 4 + 7 \times 2 - 8 \div 2 = 4 + 14 - 4 = 14 \\ 9 + 7 \times 2 - 8 \div 2 = 9 + 14 - 4 = 19 \\ 12 + 7 \times 2 - 8 \div 2 = 12 + 14 - 4 = 22

Hope this helps.
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Whats 1+1 Plz help enjoy the points hehe
AleksandrR [38]

Answer:

2

Step-by-step explanation:

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