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KATRIN_1 [288]
3 years ago
8

A digit is written to the right of the units digit of 757. If the resulting four-digit number is divisible by 3, how many possib

ilities are there for the digit that was written?
Mathematics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

3

Step-by-step explanation:

It is a well known trick that when you add together the digits of a number, if they are a multiple of 3 then the number is divisible by 3. Let's go through the options and check them:

7+5+7+0=19 not a multiple of 3

7+5+7+1=20 not a multiple of 3

7+5+7+2=21 multiple of 3

7+5+7+3=22 not a multiple of 3

7+5+7+4=23 not a multiple of 3

7+5+7+5=24 multiple of 3

7+5+7+6=25 not a multiple of 3

7+5+7+7=26 not a multiple of 3

7+5+7+8=27 multiple of 3

7+5+7+9=28 not a multiple of 3

As you can see, only 3 of these were possibilities that satisified the conditions. Hope this helps!

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PLEASE HELP!! WILL GIVE BRAINLY!
irina1246 [14]

Answer:

Step 1: 10 group(s) of 23=230

Step 2: 6 group(s) of 23=138

Step 3: Add the partial quotients: 10 + 6 = 16

Step-by-step explanation:

7 0
2 years ago
The terminal side of θ passes through the point (10, 6). What is the exact value of cos θ in simplified form?
seraphim [82]

Answer:

\frac{5\sqrt{34}}{34}

Step-by-step explanation:

The formula for cos θ is a/r. A is the first number (10) and b is the second number (6). R is the hypoteneuse which can be found through r = \sqrt{a^{2} + b^{2}  }.

In the equation you'd write that as r = \sqrt{10^{2} + 6^{2} which can be simplified to \sqrt{136.

You end up with \frac{10}{\sqrt{136} } and you simplify this by doing \frac{10 }{\sqrt{136} } * \frac{\sqrt{136} }{\sqrt{136} }, ending with the result of \frac{5\sqrt{34}}{\sqrt{34} }.

(I also got this answer right on the test.)

5 0
3 years ago
Please help me I can’t figure out how to solve
kirza4 [7]
I don’t know how to do it,, but use photomath, it’s perfect for these type of questions
8 0
3 years ago
Read 2 more answers
Measurements of the sodium content in samples of two brands of chocolate bar yield the following results (in grams):
Tpy6a [65]

Answer:

98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .

Step-by-step explanation:

We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;

Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95

Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60

Also, \mu_X represent the population mean for Brand B and let \mu_Y represent the population mean for Brand A.

Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;

        P.Q. = \frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where, Xbar = Sample mean for Brand B data = 36.9

            Ybar = Sample mean for Brand A data = 32.9

              n_1  = Sample size for Brand B data = 13

              n_2 = Sample size for Brand A data = 9

              s_p = \sqrt{\frac{(n_1-1)s_X^{2}+(n_2-1)s_Y^{2}  }{n_1+n_2-2} } = \sqrt{\frac{(13-1)*10.4+(9-1)*7.1 }{13+9-2} } = 3.013

Here, s^{2}_X and s^{2} _Y are sample variance of Brand B and Brand A data respectively.

So, 98% confidence interval for the difference μX−μY is given by;

P(-2.528 < t_2_0 < 2.528) = 0.98

P(-2.528 < \frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  } } < 2.528) = 0.98

P(-2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} < (Xbar -Ybar) -(\mu_X-\mu_Y) < 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ) = 0.98

P( (Xbar - Ybar) - 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} < (\mu_X-\mu_Y) < (Xbar - Ybar) + 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ) = 0.98

98% Confidence interval for μX−μY =

[ (Xbar - Ybar) - 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} , (Xbar - Ybar) + 2.528 * s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} ]

[ (36.9 - 32.9)-2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9} , (36.9 - 32.9)+2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9} ]

[ 0.697 , 7.303 ]

Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .

                     

4 0
3 years ago
Find the selling price of a $7.50 agenda book with a 15% discount.
Diano4ka-milaya [45]

Answer:

The selling price of the agenda book is $6.38 to the nearest cent.

Step-by-step explanation:

Assume that the cost price of the agenda book is 100%

∵ The discount is 15%

∵ The selling price = the cost price - discount amount

∴ The selling price = 100% - 15%

→ That means the selling price is 85% of the cost price

∵ The cost price = $7.50

∴ The selling price = 85% × 7.50

→ Change 85% to a number by divide it by 100

∴ The selling price = \frac{85}{100} × 7.50

∴ The selling price = 6.375

→ Round it to the nearest cent (2 d.p)

∴ The selling price = $6.38

∴ The selling price of the agenda book is $6.38 to the nearest cent.

8 0
3 years ago
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