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olchik [2.2K]
3 years ago
15

Jan has a 12 ounce milkshake. Four ounces in the milkshakes are vanilla, and the rest is chocolate. What equivalent fractions th

at represent the fraction of the milkshake that is vanilla
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

Vanilla milkshake = 1/3 and Chocolate milkshake = 2/3

Step-by-step explanation:

Given data:

Total ounce of milkshake = 12 ounce

Vanilla milkshake = 4

Chocolate is the rest <em>which can be interpreted as 12 - 4= 8 ounce</em>

Representing as fractions

<em>Vanilla milkshake = </em>4/12 <em>(Reducing to lowest terms that is diving numerator and denominator by common factor in this case 4)</em>

Vanilla milkshake = 1/3

Chocolate milkshake = 8/12 <em>(Reducing to lowest terms that is diving numerator and denominator by common factor in this case 4)</em>

Chocolate milkshake = 2/3

<em />

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Answer:

 - 10 y+10.2

Step-by-step explanation:

4-2y+(-8y)+6.2

combine like terms

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Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 ​ of a blanke
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Answer:


Step-by-step explanation:

Given that Darcie wants to donate minimum 3 blankets to donate to a homeless shelter.  No of days left =60

No of days to complete one blanket = 1/(1/15) = 15 days

Hence in 60 days she has to complete ≥3 blankets

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No of days she can skip crocheting ≤15

Let x be the no of days crocheted and y no of days skipped

Then x+y≤60

See the graph attached as x axis for days crocheted and y for days skipped

No of blankets can be either 3 or 4.


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3 years ago
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1,384 is: rational irrational
kirill [66]
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3 years ago
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An automobile manufacturer has discovered that 20% of all the transmissions it installed in a particular style of truck are defe
Hatshy [7]

Answer:

0.148 = 14.8% probability that they will need to order at least one more new transmission

Step-by-step explanation:

For each transmission, there are only two possible outcomes. Either it is defective after a year of use, or it is not. The probability of a transmission being defective is independent of any other transmission. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all the transmissions it installed in a particular style of truck are defective after a year of use.

This means that p = 0.2

Sold seven trucks:

This means that n = 7

It has two of the new transmissions in stock. What is the probability that they will need to order at least one more new transmission?

This is the probability that at least 3 are defective, that is:

P(X \geq 3) = 1 - P(X < 3)

In which

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{7,0}.(0.2)^{0}.(0.8)^{7} = 0.2097

P(X = 1) = C_{7,1}.(0.2)^{1}.(0.8)^{6} = 0.3670

P(X = 2) = C_{7,2}.(0.2)^{2}.(0.8)^{5} = 0.2753

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2097 + 0.3670 + 0.2753 = 0.852

P(X \geq 3) = 1 - P(X < 3) = 1 - 0.852 = 0.148

0.148 = 14.8% probability that they will need to order at least one more new transmission

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If you can help I’m still learning
snow_tiger [21]

Answer:

It’s +16

Step-by-step explanation:

7 0
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