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Alchen [17]
3 years ago
5

A specialty store sells items that are priced at exactly $3, $5, or $10. The store manager figures that 16% of inventory is pric

ed at $3, 32% is priced at $5, and 52% is priced at $10. With this in mind, what is the average price of any item in the store?
Mathematics
2 answers:
Elza [17]3 years ago
7 0

Answer:

$7.28

Step-by-step explanation:

The average price, or the expected price, of any item in this specialty store is given by the weighted average of each item's price. That is, the sum of the products of each individual price by its corresponding sales mix:

AP =(0.16*\$3)+(0.32*\$5)+(0.52*\$10)\\AP=\$7.28

The average price of any item in the store is $7.28

Mars2501 [29]3 years ago
7 0

Answer:

7.28

Step-by-step explanation:

0.16 * 3 = 0.48

0.32 * 5 = 1.6

0.52 * 10 = 5.2

The sum of all these numbers gives you 7.28

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Answer:

The true statements are:

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Step-by-step explanation:

The given data are:  35, 41, 18, 75, 36, 21, 62, 29, 154, 70

Make the data in order from the least to the greatest

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So, the median of the data = (36 + 41)/2 = 38.5

We can deduce that The number 154 represents an outlier because the difference between 154 and 75 is much greater than the difference between the other data

If we divided the data to two groups , they will be:

(18 , 21 , <u>29 </u>, 35 , 36)  ,  (41 , 62 , <u>70 </u>, 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

And the interquartile range = Q2 - Q1 = 70 - 29 = 41

So, the true statements are:

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