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svet-max [94.6K]
3 years ago
10

Help me with this please .

Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

2.09<2.1

Step-by-step explanation:

2.09   < 2.1

Take one number and subtract the other.

If you get a positive, then the first number is larger.  If you get a negative,  then the second number is larger.


I think 2.1 is larger

2.1

-2.09

-------------

Borrow from the 1

2. 0  10

-2. 0 9

---------------

0.  0 1

Since this is positive, 2.1 is larger

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Lim (x+1) (3x^2-9)<br> X2
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Answer:

\lim_{x \to 2} (x+1)(3x^2-9) = 9

Step-by-step explanation:

Step 1: Write out limit

\lim_{x \to 2} (x+1)(3x^2-9)

Step 2: Evaluate

(2 + 1)(3(2)² - 9)

3(3(4) - 9)

3(12 - 9)

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Negative x + 10.2 minus one-half x + y
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Convert 5 2/7 to 7ths<br> (there’s the image if you’re confused.)
MrMuchimi

Answer:

37/7

Step-by-step explanation:

to get 37-

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7 0
2 years ago
Please help! Explain how to solve!
Gnesinka [82]
So this one is a little tricky because in order to solve you need to combine like terms. The only problem is that two fractions don't have the same denominator.
This is what you do.
2/3 - 1/9
= (2*9) - (1*3) / 3*9
= 18 - 3 / 27
= 15/ 27
Simplify.
5/9 + y = 7/9
Now since you need to isolate the variable you have to subtract 5/9 from both sides. Since the denominator is the same you can just subtract the numerator. 
So y = 2/9
I hope this helps love! :)
3 0
3 years ago
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