Answer:
(4)(2) - (-5)(2)
8 - (-10)
8 + 10
18
Step-by-step explanation:
Simple division. 269/48=5.60416666667. You probably cannot put decimals, so round to 6.
Answer:
sorry i don't speak spanish but if i did i would have gave u the answer
Step-by-step explanation:
Using the binomial probability concept ; the probability of obtaining 10 or more heads is 0.0457
Recall :
P(x = x) = nCx * p^x * q^(n-x)
Where :
- n = number of trials = 12
- x ≥ 10
- p = probability of success = 0.5
- q = 1 - q = 0.5
P(x ≥ 10) = P(x = 10) + P(x = 11) + P(x = 12)
Using a binomial probability calculator :
P(x = 10) =
P(x = 11) =
P(x = 12) =
P(x ≥ 10) = 0.01611 + 0.02930 + 0.000244
P(x ≥ 10) = 0.045654
Therefore, probability of getting <em>as</em><em> </em><em>extreme</em><em> </em><em>or</em><em> </em><em>more</em><em> </em><em>extreme</em><em> </em><em>than</em><em> </em><em>10</em><em> </em><em>heads</em><em> </em><em>is</em><em> </em>0.0457.
Learn more :brainly.com/question/12474772
The probability that the Yankees would score fewer than 5 runs when they lose the game is 0.44.
<h3>What is probability?</h3>
It is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
The probability that the Yankees will win a game P(win) = 0.57
The probability that the Yankees will score 5 or more runs in a game is:
P(s>5) = 0.46
The probability that the Yankees lose and score fewer than 5 runs is:
P(s<5) = 0.33
To find the probability that the Yankees would score fewer than 5 runs when they win the game:
This is the case of probabilities of one event and another event together we will multiply the respective probabilities of the event:
= 0.57 + 0.33 - 0.46
= 0.44
Thus, the probability that the Yankees would score fewer than 5 runs when they lose the game is 0.44.
Learn more about the probability here:
brainly.com/question/11234923
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