Question

The area of the base of a rectangular prisim four and three fourths and the height of two and one third what is the volume

Answer 1

Data:
$A_{base} = 4 \frac{3}{4} = \frac{4*4+3}{4} = \frac{16+3}{4} \to A_{base} = \frac{19}{4}$

$h (height) = 2 \frac{1}{3} = \frac{3*2+1}{3} = \frac{6+1}{3} \to h (height) = \frac{7}{3}$
$v (volume) = ?$

Formula: $V = A_{b}*h$

Solving:
$V = A_{b}*h$
$V = \frac{19}{4} * \frac{7}{3}$
$V = \frac{133}{12}$
$V = 11.08333....$
$\boxed{\boxed{V \approx 11.08}}\end{array}}\qquad\quad\checkmark$