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amm1812
3 years ago
5

The first and last terms of a 52-term arithmetic series are listed in the table. What is the sum of the series?

Mathematics
1 answer:
inna [77]3 years ago
6 0

sum = x(n+1)/2

where x is the number of the term ( in this case 52)

 n is the last number in the series( which is not given in the problem)

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Wangari plants trees at a constant rate of 1212 trees every 33 hours. Write an equation that relates pp, the number of trees Wan
igor_vitrenko [27]

Answer:

p=4h    

Step-by-step explanation:

Let p be the number of trees Wangari plants, and h  be the time she spends planting them in hours.

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Let us find number of trees planted in 1 hour by dividing 12 by 3.

\text{Number of trees planted in 1 hour}=\frac{12\text{ plants}}{3\text{ hour}}

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I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
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