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3 years ago

#31 please help and show work thank you in advance

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

6 0

The base price of the car is about $22,196 because:

x= major options package

10x + x = 24,416

*the 10x is the price of the car

This then simplifies to

11x = 24,416

use division.

The destination charge is not needed unless you want to check your answer. If you have to then you would do the same thing. The equation would be:

y= destination charge

5y + y = 24,416

Hope this helps.

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Is (10, 5) a solution to this system of inequalities? 20x + 4y > 5 x + y < 15

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3 years ago

If ?/100 = 0.2 then ? =

Olegator [25]

Answer:

Step-by-step explanation:

x / 100 = 0.2

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2 years ago

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Tim purchases a new bike for $72.99. A 5% sales tax is charged for these items. What is the total cost, including

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2 years ago

A pumpkin is launched directly upwards at 72 feet per second from a platform 24 feet high. The pumpkins height, h, at time t sec

STALIN [3.7K]

Answer: Maximum height = 105 feet

And, It takes 9/4 seconds to reach that point.

Step-by-step explanation:

Here the given function that shows the height of the pumpkin,

$h(t) = -16t^2 + 72t + 24$ --------(1)

Where t is the time in second.

Differentiating equation (1) with respect to t,

We get, $h'(t) = -32 t + 72$

Again differentiating above equation with respect to t,

We get, $h''(t) = -32$

For maximum or minimum, $h'(t) = 0$

$- 32 t + 72 = 0$

$32 t = 72$

$t = \frac{9}{4}$

At t = 9/4 , h''(t) = Negative value,

Therefore, At t = 9/4 seconds, h(t) is maximum,

And, the maximum value is,

$h(\frac{9}{4} ) = -16(\frac{9}{4})^2 + 72(\frac{9}{4}) + 24$

$h(\frac{9}{4} ) = -16(\frac{81}{16})+ 72(\frac{9}{4}) + 24$

$h(\frac{9}{4} ) = -81 + 162 + 24=105$

Therefore, the maximum height of the pumpkin is 105 feet at 9/4 seconds

8 0

3 years ago

Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX is translated 4 units right and 3 uni

IRINA_888 [86]

WKLX
W(2, −3),
K(4, −3),
L(5, −2) ,
X(1, −2)

TRANSLATED 4 UNITS RIGHT and 3 UNITS DOWN to produce W'K'L'X

4 units right means the x coordinate is affected. Since the moving to the right, we add 4 to the x values of each vertice.

W = 2 + 4 = 6
K = 4 + 4 = 8
L = 5 + 4 = 9
X = 1 + 4 = 5

3 units down means the y axis is affected. We add 3 to the value of y but keep the negative sign.
W = -3 + -3 = -6
K = -3 + -3 = -6
L = -2 + -3 = -5
X = -2 + -3 = -5

The correct answer is: W′(6, −6), K′(8, −6), L′(9, −5) , and X′(5, −5)

6 0

3 years ago