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3 years ago

notebooks cost $1.20 each this weekend they will be on sale for $0.80 what percentage off of the orignal sale

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

6 0

Answer:

40 % off

Step-by-step explanation:

First you are going to 1.30, then divided that by 0.80

tangare [24]3 years ago

5 0

Answer:

33%

Step-by-step explanation:In the question it is already given that the actual cost of each notebook is $1.20. For the weekend, the notebooks would sold at a discounted rate of $0.80

The amount of discount during the weekend = (1.20 - 0.80) dollars

= 0.40 dollars

So the amount of discount given during the weekend is $0.40

Now we need to find the percentage of discount given during the weekend.

Then

Percentage of discount during the weekend = (0.40/1.20) * 100

= 0.33 * 100

= 33

Then the percentage of discount given is 33%.

You might be interested in

Suppose that the functions s and t are defined for all real numbers x as follows.

PolarNik [594]

Answer:

(s-t)(-1) = -1

(s+t)(-1) = -7

Step-by-step explanation:

Given the following set of functions

s(x)=2x-2

t(x)=3x

(s-t)(x) = s(t) - t(x)

(s-t)(x) = 2x - 2 - 3x

(s-t)(x) = -x -2

(s-t)(-1) = -(-1) - 2

(s-t)(-1) = 1-2

(s-t)(-1) = -1

(s+t)(x) = s(t) + t(x)

(s+t)(x) = 2x - 2 + 3x

(s+t)(x) = 5x -2

(s+t)(-1) = 5(-1) - 2

(s+t)(-1) = -5-2

(s+t)(-1) = -7

8 0

3 years ago

A spinner is divided into 8 section of equal size. The sections are numbered 1 through 8. Use this information to determine the

olga_2 [115]

1) 1/8

2) 1/2

Step-by-step explanation:

First of all, we notice that the spinner is divided into 8 sections of equal size.

So the number of sections is

n = 8

Secondly, we note that each section has the same size: this means that the probability of the spinner landing on each section is the same.

The probabilty of a certain event A to occur is given by

$p(A)=\frac{a}{n}$

where

a is the number of successfull outcomes (in which A occurs)

n is the total number of possible outcomes

Here we want to find

$p(7)$ = probability that the spinner lands on section 7

Here we have:

$a=1$ (only 1 outcome is successfull: the one in which the spinner lands on section 7)

$n=8$

Therefore, the probability is

$p(7)=\frac{1}{8}$

Here we want to find the probability that the spinner lands on an even numbered section.

As before, the total number of possible outcomes his:

$n=8$

which corresponds to: 1, 2, 3, 4, 5, 6, 7, 8

The even-numbered sections are:

2, 4, 6, 8

So, the number of successfull outcomes is

$a=4$

Because there are only 4 even-numbered sections.

Therefore, the probability that the spinner lands on an even numbered section is:

$p(e)=\frac{a}{n}=\frac{4}{8}=\frac{1}{2}$

8 0

3 years ago

Write the polynomial f(x)=x^4-10x^3+25x^2-40x+84. In factored form

Verizon [17]

<h2>Steps:</h2>

So firstly, to factor this we need to first find the potential roots of this polynomial. To find it, the equation is $\pm \frac{p}{q}$ , with p = the factors of the constant and q = the factors of the leading coefficient. In this case:

$\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84$

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

$f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}$

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

3 | 1 - 10 + 25 - 40 + 84
_________________

Firstly, drop the 1:

3 | 1 - 10 + 25 - 40 + 84
↓
_________________
1

Next, multiply 3 and 1, then add the product with -10:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3
_________________
1 - 7

Next, multiply 3 and -7, then add the product with 25:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21
_________________
1 - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12
_________________
1 - 7 + 4 - 28

Lastly, multiply -28 and 3, then add the product with 84:

3 | 1 - 10 + 25 - 40 + 84
↓ + 3 - 21 + 12 - 84
_________________
1 - 7 + 4 - 28 + 0

Now our synthetic division is complete. Now since the degree of the original polynomial is 4, this means our quotient has a degree of 3 and follows the format $ax^3+bx^2+cx+d$ . In this case, our quotient is $x^3-7x^2+4x-28$ .

So right now, our equation looks like this:

$f(x)=(x-3)(x^3-7x^2+4x-28)$

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

$f(x)=(x-3)(x^2(x-7)+4(x-7))$