1) $375
500 *.25= 125
500-125= 375
2) (5/8)* 32= 20 girls in class
(3/8)* 32= 12 BOYS in class
4) 19+42+X=87
62+X= 87 (add 19 and 42 together )
X=25 ( subtract 87 from 62)
Answer:
don't know sorry
Step-by-step explanation:
dont know sorry
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
The arc length, radius and the included angle are related as
where
is in radians.
The radius
is given by

Correct choice is (B).