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Digiron [165]
3 years ago
13

Help with this question

Mathematics
1 answer:
larisa [96]3 years ago
4 0

Answer:

-2

Step-by-step explanation:

2x + y = 10               Subtract 2x from both sides.

2x-2x + y = 10 - 2x  Combine the left.

y = 10 - 2x

The slope is the number in front of the x -- in this case - 2

The answer is - 2

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Step-by-step explanation:

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Jobisdone [24]

The question is:

Check whether the function:

y = [cos(2x)]/x

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Answer:

To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.

Let us do that.

y = [cos(2x)]/x

y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]

Now,

xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x

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