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3 years ago

8

Please help jandfjbnsjdfnbsd

2 answers:

klemol [59]3 years ago

5 0

Ax^{2}+bx+c
to factor, find numbers that add up to b but multiply to c. these would by 3 and 2

(x+2)(x+3), so D would be a factor

damaskus [11]3 years ago

5 0

X² + 5x + 6
x 3
x 2

(x+3)(x+2)

to find this, you must get two numbers (or variables) that will give you the number on the top when multiplied, while giving you the number in the middle when added together.
To prove this, do the FOIL method when you are solve the binomials & make it into a trinomial

x(x) = x^2
x(3) = 3x
x(2) = 2x
3(2) = 6
x^2 + 3x + 2x + 6
x^2 + 5x + 6 (simplify numbers with similar variables)

(x+3) is your answer (in this case, since it does not ask you to choose both, and (x+2) is not a choice

hope this helps

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Answer:

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Read 2 more answers

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

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