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Deffense [45]
3 years ago
12

Solve the following equations : 2(x -1) + 3(x +1)=4(x+4)

Mathematics
1 answer:
madreJ [45]3 years ago
3 0
This is how I'd work it:

2(x-1)+3(x+1)=4(x+4)
     2x-2+3x+3=4x+16
              5x+1=4x+16
                    <u>x=15</u>

To check, substitute x into the original equation and solve: 

2(15-1)+3(15+1)=4(15+4)
                28+48=76
                      76=76 
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Naya [18.7K]

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andrezito [222]
(9 - 7 X 3 + 4 )²
Always follow the rule
BIDMAS

Brackets
Indices
Division
Multiplication
Addition
Subtraction

First look at the Brackets
There are no indices in the brackets
There is no division in the brackets
There is a Multiplication in the brackets    7 x 3


For the answer

(9 - 7 x 3 + 4)²
Brackets
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(9 - 21 + 4)²
Addition   -21 + 4 = -17
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Now start again once the brackets are gone
-8²
Indices
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