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daser333 [38]
3 years ago
6

What number is 60 percent of 29

Mathematics
1 answer:
nevsk [136]3 years ago
7 0
60% is 0.60 so you do 0.60 x 29 which = to 17.4
so your answer is 17.40 or 17.4 is 60% of 29
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X-9= 1/4x + (1/4x + 12) + (1/4x - 3) what’s that answer?
konstantin123 [22]

Answer:

x = 72

Step-by-step explanation:

Make the problem simpler by eliminating the fractional coefficients:

x-9= 1/4x + (1/4x + 12) + (1/4x - 3), when multiplied by 4, becomes:

4x - 36 = x + x + 48 + x - 12

Summing up all the x terms, we get:

4x - 2x - x = 48 - 12 + 36

Then x = 72

7 0
3 years ago
4 (negative one-half x + 7) + 5 x = 15
Ronch [10]

Answer:

Step 3 is incorrect

Step-by-step explanation:

4(-1/2x + 7) + 5x = 15

-2x + 28 + 5x = 15

3x + 28 = 15

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3 years ago
How much interest will $1,200 earn over 10 years with 5% interest compounded annually
Amiraneli [1.4K]

Answer:

$1,954

Step-by-step explanation:

4 0
2 years ago
Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!
I am Lyosha [343]

Answer:

13 l of 15%, 13 l of 25%, 26 l of 70%

Step-by-step explanation:

solutions:

  • 15%, 25% and 70%

final solution:

  • 52 l of 45%

This includes 0.45*52l= 23.4 l acid

Let's assume:

  • amount of 15% solution= x
  • amount of 25% solution= y
  • amount of 70% solution= z
  • and we have z=2y

so there are 2 equation:

  • x+y+z=52
  • 0.15x+0.25y+0.7z=23.4

or

  • x+y+2y= 52 ⇒ x+3y= 52 ⇒ x= 52- 3y
  • 0.15x+0.25y+1.4y=23.4
  • 0.15x+1.65y=23.4
  • 0.15*(52-3y)+1.65y=23.4
  • 7.8-0.45y+1.65y=23.4
  • 1.2y=23.4-7.8
  • 1.2y= 15.6
  • y=15.6/1.2
  • y= 13 l

--------

  • x= 52- 3*13= 13 l
  • z= 2y= 2*13= 26 l
6 0
3 years ago
17. Which of the following is a factor of both x^2 - x - 6 and x^2- 5x+6?
andreyandreev [35.5K]

Step-by-step explanation:

For the equation x^{2} - x - 6, factoring gives us the following:

(x - 3)(x + 2)

For the equation x^{2} - 5x + 6, factoring gives us the following:

(x - 3)(x - 2)

From this, we see that the common factor is (x - 3)

7 0
3 years ago
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