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sergeinik [125]
3 years ago
9

Which ordered pair is a solution of the equation? − 7 x + 3 y = 2 −7x+3y=2

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

Hello There. ☆~\---___`:•€`___---/~☆ The correct answer is C. Both (1,3) and (-2,-4).

To check whether (-2,-4) is a solution of the equation let's substitute x= -2 and y= -4 into the equation:

-7x+3y=2

-7*(-2)+3*(-4)=2

14-12=2

2=2

Do the same thing with (1,3)

-7x + 3y = 2

-7 * 1 + 3 * 3 = 2

-7 + 9 = 2

2 = 2.

Hope It Helps!~ ♡

ItsNobody~ ☆

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What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
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Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

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x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

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To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

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