What is another way to write 3x(4+5)=27
2 answers:
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Answer:
1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64
2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21
Step-by-step explanation:
1. Maximize: P = 4x +4y
Subject to: 2x + y ≤ 20
x + 2y ≤ 16
x, y ≥ 0
Plot the constraints and the objective function Z, or P=4x+4y)
Push the objective function to the limit permitted by the feasible region to find the maximum.
Answer: Objective function is a maximum at (16,0),
Z = 4x+4y = 4(16) + 4(0) = 64
2. Maximize P = 3x + 2y
Subject to x + y ≤ 8
2x + y ≤ 13
x ≥ 0, y ≥ 0
Plot the constraints and the objective function Z, or P=3x+2y.
Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.
Answer: Objective function is at a maximum at (5,3),
Z = 3x+2y = 3(5)+2(3) = 21
Answer:
9x=19 step by step solution has been attached to this answer
The factors of the given expression are x , x - 2 and x - 4
![V(x)= x^{3}- 6x^{2}+8x \\ \\ V(x)=x( x^{2} -6x+8) \\ \\ V(x)=x( x^{2} -2x-4x+8) \\ \\ V(x)=x[x(x-2)-4(x-2)] \\ \\ V(x)=x(x-2)(x-4)](https://tex.z-dn.net/?f=V%28x%29%3D%20x%5E%7B3%7D-%20%206x%5E%7B2%7D%2B8x%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28%20x%5E%7B2%7D%20-6x%2B8%29%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28%20x%5E%7B2%7D%20-2x-4x%2B8%29%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%5Bx%28x-2%29-4%28x-2%29%5D%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28x-2%29%28x-4%29%20)
So the expression for height and length are x and x - 4
So the expression for height and length are x and x - 4